- #1

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- Homework Statement:
- A conic surface is placed Inside a region filled with uniform Electric Field E. The field lines are perpendicular to the geratrix AB. The cone has height h and radius R of it's base. Find the electric flux through the lateral surface of the cone.

- Relevant Equations:
- Ø=E.S.cosx Øtot=qint/€ (gaus law)

Since there is no charge inside the cone, the total flux through its surface is zero, hence Ø(lateral surface)+∅(base surface)=0. But ∅(base surface)=E.πR².cosΩ, because electric Field is homogenous. But by the figure, Ω is just arctg(h/R).

So Ø(lateral surface)=-E.π.R².R/√(R²+h²).

This is not the answer according to the solution I saw. My point is, does anyone could show me where is my mistake?

So Ø(lateral surface)=-E.π.R².R/√(R²+h²).

This is not the answer according to the solution I saw. My point is, does anyone could show me where is my mistake?